在單片機上能實現:用定時器0的方式1實現第一個發光管一200ms間隔閃爍,用定時器1的方式1實現數碼管前兩位59s循環計時,c語言程序代碼如下:
#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit dula=P2^6;
sbit wela=P2^7;
sbit led1=P1^0;
uchar code table[]={
0xc0,0xf9,0xa4,0xb0,
0x99,0x92,0x82,0xf8,
0x80,0x90,0x88,0x83,
0xc6,0xa1,0x86,0x8e};
void delayms(uint);
void display(uchar,uchar);
uchar num,num1,num2,shi,ge;
void main()
{TMOD=0x11;
TH0=(65536-45872)/256;
TL0=(65536-45872)%256;
TH1=(65536-45872)/256;
TL1=(65536-45872)%256;
EA=1;
ET0=1;
ET1=1;
TR0=1;
TR1=1;
while(1)
{
display(shi,ge);
}
}
void display(uchar shi ,uchar ge)
{
dula=1;
P0=table[shi];
dula=0;
P0=0xfe;
wela=1;
P0=0xfe;
wela=0;
delayms(5);
dula=1;
P0=table[ge];
dula=0;
P0=0xfe;
wela=1;
P0=0xfe;
wela=0;
delayms(5);
}
void delayms(uint xms)
{
uint i,j;
for(i=xms;i>0;i--)
for(j=110;j>0;j--);
}
void TO_time() interrupt 1
{
TH0=(65536-45872)/256;
TL0=(65536-45872)%256;
num1++;
if(num1==4)
{
num1=0;
led1=~led1;
}
}
void T_time()interrupt 3
{
TH1=(65536-45872)/256;
TL1=(65536-45872)%256;
num2++;
if(num2==20)
{
num2=0;
num++;
if(num==60)
num=0;
shi=num/10;
ge=num%10;
}
}
|