16位有符號(hào)數(shù)據(jù)排序成功 16位無符號(hào)和32位長整型數(shù)據(jù)排序不行?

ID:91150 · 發(fā)表于 2024-9-17 11:31

網(wǎng)上抄來例程 16位有符號(hào)數(shù)據(jù) 快速排序成功，而16位無符號(hào)和32位長整型數(shù)據(jù)排序不能通過。
請(qǐng)各位指教，哪里沒有弄好，應(yīng)該怎么辦？謝謝

單片機(jī)源程序如下:

#include "STC32G.h"
#include "stdio.h"
#include "intrins.h"
typedef unsigned char u8;
typedef unsigned int u16;
typedef unsigned long int u32;
#define SYSCLK 132710400UL/6 //13....M/6=22.1184M
#define BRT (65536 - SYSCLK/4/19200) //
bit busy;
u8 i;
int aaa[6]={8,2,3,1,7,0};
int bbb[6];
//int AQ[5] = {123,1,521,400,619};
//int arry[12] = {123,1,501,8,2,400,3,1,7,0,400,319};
int arry[12] = {123,1,31501,8,2,400,3,1,7,0,21400,319};
//u8 arry[12] = {123,1,201,8,2,200,3,1,7,0,100,219};
//u32 arry[12] = {123,1,95201,8,10000,200,3,1,7,0,100,109219};
//u16 arry[12] = {123,1,25201,8,10000,200,3,1,7,0,100,9219};
/*=======延時(shí)函數(shù) 大約1mS===========*/
void delay_ms(u16 ms)
{ u16 i;
do
{i = SYSCLK / 6000;
while(--i) ;
}while(--ms);
}
/*****Uart1Init********************************/
void Uart1Init(void) //19200bps@22.1184MHz
{ SCON = 0x50; //8位數(shù)據(jù),可變波特率
AUXR |= 0x01; //串口1選擇定時(shí)器2為波特率發(fā)生器
AUXR |= 0x04; //定時(shí)器時(shí)鐘1T模式
T2L = 0xE0; //設(shè)置定時(shí)初始值
T2H = 0xFE; //設(shè)置定時(shí)初始值
AUXR |= 0x10; //定時(shí)器2開始計(jì)時(shí)
ES=1;
EA=1;
}
/*=======發(fā)字節(jié) =========== */
void Uart1Send(u8 dat)
{ while (busy);
busy = 1;
SBUF = dat;
}
/******************/
#pragma FUNCTIONS (reentrant) //F1幫助里: C251 generates reentrant CODE
//void quiksort(u16 a[],u16 low,u16 high)//reentrant
//void quiksort(u8 a[],int low,int high)//reentrant
//void quiksort(u32 a[],u32 low,u32 high)//reentrant
void quiksort(int a[],int low,int high)//reentrant
{ int i = low;
int j = high;
int temp = a[i];
//u32 i = low;
//u32 j = high;
//u32 temp = a[i];
//u16 i = low;
//u16 j = high;
//u16 temp = a[i];
if( low < high)
{while(i < j)
{while((a[j] >= temp) && (i < j))
{j--;
}
a[i] = a[j];
while((a[i] <= temp) && (i < j))
{i++; //Uart1Send(0x1A);
}
a[j]= a[i];
}
a[i] = temp;
quiksort(a,low,i-1);
quiksort(a,j+1,high);
}
}
void main()
{ WTST = 0x00;
P_SW2 = 0x80;
EAXFR = 1; //擴(kuò)展寄存器(XFR)訪問使能
CKCON = 0; //提高訪問XRAM速度
P0M0 = 0x00; P1M0 = 0x00; P2M0 = 0x00; P3M0 = 0x00;
P0M1 = 0x00; P1M1 = 0x00; P2M1 = 0x00; P3M1 = 0x00;
P4M0 = 0x01; P5M0 = 0x00; P6M0 = 0x00; P7M0 = 0x00;
P4M1 = 0x00; P5M1 = 0x00; P6M1 = 0x00; P7M1 = 0x00;
Uart1Init();
Uart1Send(0x1A);Uart1Send(0x2A);Uart1Send(0x3A);Uart1Send(0x4A);
while (1)
{ delay_ms(550);
Uart1Send(0xAA);Uart1Send(0xAA);
for(i=0;i<12;i++)
//{Uart1Send((u8)((int)(arry[i])>>8)); //
// Uart1Send((u8)((int)(arry[i]) ));
{Uart1Send((u8)((u16)(arry[i])>>8)); //
Uart1Send((u8)((u16)(arry[i]) ));
//{Uart1Send((u8)((u16)(arry[i])>>8)); //
//{ Uart1Send((arry[i]) );
// {Uart1Send((u8)((arry[i])>>16)); //
// Uart1Send((u8)((arry[i])>>8 ));
// Uart1Send((u8)((arry[i]) ));
}
Uart1Send(0xCC);Uart1Send(0xCC);//quiksort(arry,0,4);
//----？？？----------------
quiksort(arry,0,11);
//----？？？----------------
delay_ms(550);
Uart1Send(0xBB);Uart1Send(0xBB);
for(i=0;i<12;i++)
//{Uart1Send((u8)((int)(arry[i])>>8)); //
//Uart1Send((u8)((int)(arry[i]) ));
{Uart1Send((u8)((u16)(arry[i])>>8)); //
Uart1Send((u8)((u16)(arry[i]) ));
//{Uart1Send((u8)(u32)(arry[i])>>16)); //
// Uart1Send((u8)(u32)(arry[i])>>8 ));
// Uart1Send((u8)(u32)(arry[i]) ));
}
}
}
/******************************************* */
void Uart1Isr() interrupt 4
{ if (TI)
{ TI = 0;
busy = 0;
}
if (RI)
{RI = 0;
}
}

復(fù)制代碼

ID:844772 · 發(fā)表于 2024-9-17 20:01

我在用手機(jī)看，32位排序每次都不能成功嗎？這是八位機(jī)，你這種超過八位的運(yùn)算不要開中斷

ID:744809 · 發(fā)表于 2024-9-18 09:09

你quiksort函數(shù)的入?yún)⒍际莍nt類型的，51里面int類型是16位有符號(hào)數(shù)，范圍是-32768到32767；而16位無符號(hào)數(shù)是0-65535，32位無符號(hào)數(shù)就更大了，所以你排序肯定是失敗的。如果想排序16位無符號(hào)數(shù)可以把入?yún)㈩愋透臑閡nsigned int,排序32位無符號(hào)數(shù)可以把入?yún)㈩愋透臑閡32

ID:91150 · 發(fā)表于 2024-9-18 15:29

謝謝先生們指教。
在keil 5 C251下試驗(yàn) 對(duì)應(yīng)變量數(shù)據(jù)類型在子函數(shù)里相同都是u16或
u32，排序不成功。程序文本寫了不同類型屏蔽和去除屏蔽很方便
請(qǐng)?jiān)O(shè)置到u16或u32，試一下，看能否找到不成功的原因。
8位機(jī)應(yīng)該能處理16、32位數(shù)據(jù)，int類型(-32768~ +32767)就是16位
它就可以排序。

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16位有符號(hào)數(shù)據(jù)排序成功 16位無符號(hào)和32位長整型數(shù)據(jù)排序不行?