求解STM32的串口中斷接收數組出現接收失敗（程序很簡單，是否有邏輯問題）

ID:966387 · 發表于 2021-9-23 11:58

程序功能就是單片機接收上位機（串口助手）發送的 adbcd ；將接收的數據放入數組 Rec_array[] ；
通過 if(0 == memcmp(Rec_array, "abc", 3)) 語句，翻轉 LED ;

正常情況是數組存放了 {a,b,c,d,e}; 前三項 abc對應正確，led翻轉

但是接收數據，在 if(0 == memcmp(Rec_array, "abc", 3)) 識別時數組里只存放了 {b,0,0,0,0};
想做到發送-abcde-五位，led翻轉，再發送-aaaaa-不翻轉，再發送-abcee-翻轉

程序結構很簡單：一個usart函數，一個mian函數
usart.c文件

#include "usart.h"
#include "string.h"
#include "led.h"
#define Code_Max 5//最大值 5
u8 Rec_array[Code_Max];//存放數組
unsigned int Code_Cnt = 0;//數組變量
/*中斷初始化*/
static void USART1_NVIC_Configuration(void)
{
NVIC_InitTypeDef NVIC_InitStructure;
NVIC_PriorityGroupConfig(NVIC_PriorityGroup_0);
NVIC_InitStructure.NVIC_IRQChannel = USART_IRQ;
NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 1;
NVIC_InitStructure.NVIC_IRQChannelSubPriority = 2;
NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE;
NVIC_Init(&NVIC_InitStructure);
}
void USART1_GPIO_Configuration(void)
{
GPIO_InitTypeDef GPIO_InitStructure;
/*開啟串口GPIO時鐘*/
USART_APBxClkCmd(USART_GPIO_CLK,ENABLE);
GPIO_InitStructure.GPIO_Pin = USART_TX_GPIO_PIN;
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_AF_PP;
GPIO_InitStructure.GPIO_Speed = GPIO_Speed_50MHz;
GPIO_Init(USART_TX_GPIO_PORT,&GPIO_InitStructure);
GPIO_InitStructure.GPIO_Pin = USART_RX_GPIO_PIN;
GPIO_InitStructure.GPIO_Mode = GPIO_Mode_IN_FLOATING;
GPIO_Init(USART_RX_GPIO_PORT,&GPIO_InitStructure);
}
/*串口GPIO初始化*/
void USART1_Configuration(void)
{
USART1_NVIC_Configuration();
USART1_GPIO_Configuration();
USART_InitTypeDef USART_InitStructure;
/*開啟串口時鐘*/
USART_APBxClkCmd(USART_CLK,ENABLE);
USART_InitStructure.USART_BaudRate = USART_Baudrate;
USART_InitStructure.USART_WordLength = USART_WordLength_8b;
USART_InitStructure.USART_StopBits = USART_StopBits_1;
USART_InitStructure.USART_Parity = USART_Parity_No;
USART_InitStructure.USART_HardwareFlowControl = USART_HardwareFlowControl_None;
USART_InitStructure.USART_Mode = USART_Mode_Rx | USART_Mode_Tx;
USART_Init(USARTx,&USART_InitStructure);
USART_ITConfig(USARTx,USART_IT_RXNE,ENABLE);
USART_ITConfig(USARTx,USART_IT_TXE,DISABLE);
USART_Cmd(USARTx,ENABLE);
}
/*串口接收中斷*/
void USART1_IRQHandler(void)
{
u8 data;
if(USART_GetITStatus(USARTx,USART_IT_RXNE) != RESET)
{
data = USART_ReceiveData(USARTx);
Rec_array[Code_Cnt] = data;//存放到數組
Code_Cnt++;
if(Code_Cnt >= Code_Max)
{ Code_Cnt = 0;
}
USART_ClearITPendingBit(USARTx, USART_IT_RXNE);
}
}
/*串口接收數據函數*/
void USART1_Recive(void)
{
Code_Cnt = 0;
if(0 == memcmp(Rec_array, "abc", 3))
{
LED_BLUE;
}
if(0 == memcmp(Rec_array, "bca", 3))
{
LED_RED;
}
Rec_array[0] = Rec_array[1] = Rec_array[2] = Rec_array[3] = Rec_array[4] = 0;
}

復制代碼

usart.h

#ifndef __USART_H
#define __USART_H
#include "stm32f10x.h"
#include <stdio.h>
#define USARTx USART1
#define USART_CLK RCC_APB2Periph_USART1
#define USART_Baudrate 115200
#define USART_GPIO_CLK RCC_APB2Periph_GPIOA
#define USART_APBxClkCmd RCC_APB2PeriphClockCmd
#define USART_TX_GPIO_PORT GPIOA
#define USART_TX_GPIO_PIN GPIO_Pin_9
#define USART_RX_GPIO_PORT GPIOA
#define USART_RX_GPIO_PIN GPIO_Pin_10
#define USART_IRQ USART1_IRQn
#define USART_IRQHandler USART1_IRQHandler
void USART1_Configuration(void);
void USART1_Recive(void);
#endif

復制代碼

main.c

#include "stm32f10x.h"
#include "led.h"
#include "usart.h"
int main(void)
{
LED_GPIO_Config();
USART1_Configuration();
while (1)
{
USART1_Recive();
}
}

復制代碼

ID:702863 · 發表于 2021-9-23 14:34

void USART1_Recive(void)
{
Code_Cnt = 0; //錯誤：該全局變量一直被清除；導致只有Rec_array[0]值
}

ID:161164 · 發表于 2021-9-23 15:32

若要比較串口接收的字串
加上結束符或定時器來確認傳輸結束比較好
結束符：
每次傳輸都在結尾加上特定字符如：';'分號(abcde;)
if(data == ';')Trans_Done = 1;

定時器：
建立一個1ms定時器，在串口中斷中重載定時器并開始計時
在定時器中關閉定時器并Trans_Done = 1;

while(1)
{
if(Trans_Done)
{
Trans_Done = 0;
USART1_Recive();
}
}

ID:123289 · 發表于 2021-9-23 17:31

畫個流程圖，先走通流程，而后再寫程序。

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求解STM32的串口中斷接收數組出現接收失敗（程序很簡單，是否有邏輯問題）