不能用按鍵松手死循環等待while(!key1);,會影響數碼管動態顯示,郭天祥的類似示例只為說明一個道理,完全不能實戰,樓主這程序只要小改一下問題都解決了。
- #include<reg52.h>
- sbit key1=P3^4;
- sbit dula=P2^6;
- sbit wela=P2^7;
- #define uint unsigned int
- #define uchar unsigned char
- uchar i,j,bai,shi,ge;
- uchar code table[]={
- 0x3f,0x06,0x5b,0x4f,
- 0x66,0x6d,0x7d,0x07,
- 0x7f,0x6f,0x77,0x7c,
- 0x39,0x5e,0x79,0x71};
- void delay(uint z)
- {
- uint x,y;
- for(x=z;x>0;x--)
- for(y=110;y>0;y--);
- }
- void main()
- {
- P3=0xff;//P3口全部送高電平
- i=0;
- while(1)
- {
- if(key1==0)//按下鍵盤時鍵盤端接地為低電平
- {
- j++;//消抖
- if(key1==0&&j==2)
- {
- j=2;
- i++;
- if(i>99)
- i=0;
- shi=i/10;
- ge =i%10;
- }
- }
- else j=0;//松手
- wela=1;
- P0=0xfe;//第一個數碼管亮
- wela=0;
- dula=1;
- P0=table[shi];
- dula=0;
- delay(5);
-
- wela=1;
- P0=0xfd;//第二個數碼管亮
- wela=0;
- dula=1;
- P0=table[ge];
- dula=0;
- delay(5);
- }
- }
復制代碼
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