基于51單片機的智能紅外循跡小車程序

ID:557394 · 發表于 2019-6-14 19:17

最近剛結束單片機講座的課，在寫關于智能汽車的文章的同時自己做了一個簡單的智能循跡小車，這里采用的是光電循跡模塊，使用比較簡單，
紅外對管輸出的電壓模擬信號通過比較器轉換為了數字電平，只需要根據輸出的電平高低控制電機的正反轉，這邊附上部分單片機代碼

#include "reg52.h"

typedef unsigned int u16;
typedef unsigned char u8;

sbit left1 = P0^0;
sbit left2 = P0^1;
sbit right1 = P0^2;
sbit right2 = P0^3;

sbit IN1 = P1^4;
sbit IN2 = P1^3;
sbit IN3 = P1^2;
sbit IN4 = P1^1;

void xunji();

void main()
{
while(1)
{
      xunji();
}
}

void TurnRight()
{
IN1 = 0;
IN2 = 1;

IN3 = 0;
IN4 = 1;
}

void TurnLeft()
{
IN1 = 1;
IN2 = 0;

IN3 = 1;
IN4 = 0;
}

void Forward()
{
IN1 = 1;
IN2 = 0;

IN3 = 0;
IN4 = 1;
}

void Stop()
{
IN1 = 0;
IN2 = 0;

IN3 = 0;
IN4 = 0;
}

void xunji()
{
unsigned char flag = 0;
if((left1 == 0)&&(left2 == 0)&&(right1 == 0)&&(right2 == 0)) //0 0 0 0
      flag = 0;

if((left1 == 0)&&(left2 == 0)&&(right1 == 0)&&(right2 == 1)) //0 0 0 1
      flag = 1;

if((left1 == 0)&&(left2 == 0)&&(right1 == 1)&&(right2 == 0)) //0 0 1 0
      flag = 0;

if((left1 == 0)&&(left2 == 0)&&(right1 == 1)&&(right2 == 1)) //0 0 1 1
      flag = 1;

if((left1 == 0)&&(left2 == 1)&&(right1 == 0)&&(right2 == 0)) //0 1 0 0
      flag = 0;

if((left1 == 0)&&(left2 == 1)&&(right1 == 0)&&(right2 == 1)) //0 1 0 1
flag = 1;

if((left1 == 0)&&(left2 == 1)&&(right1 == 1)&&(right2 == 0)) //0 1 1 0
      flag = 0;

if((left1 == 0)&&(left2 == 1)&&(right1 == 1)&&(right2 == 1)) //0 1 1 1
      flag = 1;

if((left1 == 1)&&(left2 == 0)&&(right1 == 0)&&(right2 == 0)) //1 0 0 0
      flag = 2;

if((left1 == 1)&&(left2 == 0)&&(right1 == 0)&&(right2 == 1)) //1 0 0 1
      flag = 0;

if((left1 == 1)&&(left2 == 0)&&(right1 == 1)&&(right2 == 0)) //1 0 1 0
  flag = 2;

if((left1 == 1)&&(left2 == 0)&&(right1 == 1)&&(right2 == 1)) //1 0 1 1
      flag = 0;

if((left1 == 1)&&(left2 == 1)&&(right1 == 0)&&(right2 == 0)) //1 1 0 0
      flag = 2;

if((left1 == 1)&&(left2 == 1)&&(right1 == 0)&&(right2 == 1)) //1 1 0 1
      flag = 0;

if((left1 == 1)&&(left2 == 1)&&(right1 == 1)&&(right2 == 0)) //1 1 1 0
      flag = 2;

if((left1 == 1)&&(left2 == 1)&&(right1 == 1)&&(right2 == 1)) //1 1 1 1
      flag = 3;
switch(flag)
{
case(0):Forward();break;

case(1):TurnRight();break;

case(2):TurnLeft();break;

default:Stop();break;
}
}

ID:383433 · 發表于 2019-7-20 15:10

很不錯，請樓主分享一下全部代碼，1539429523@qq.com

ID:632170 · 發表于 2019-10-29 17:18

樓主可不可以給我發一份完整代碼，急用1078786909@qq.com

帳號		自動登錄	找回密碼
密碼			立即注冊

久久久久久久999_99精品久久精品一区二区爱城_成人欧美一区二区三区在线播放_国产精品日本一区二区不卡视频_国产午夜视频_欧美精品在线观看免费

基于51單片機的智能紅外循跡小車程序

評分