DAC0832簡易波形發生器，產生方波，正弦波，三角波，鋸齒波

ID:559790 · 發表于 2019-6-11 17:06

#include<reg51.h>
#include<math.h>
#include<absacc.h>
#define uchar unsigned char
#define uint unsigned int
sbit key1=P1^0;
sbit key2=P1^1;
uchar count,a=0;
code uchar Sin[256]={0x80,0x83,0x86,0x89,0x8d,0x90,0x93,0x96,0x99,0x9c,0x9f,0xa2,0xa5,0xa8,0xab,0xae,0xb1,
0xb4,0xb7,0xba,0xbc,0xbf,0xc2,0xc5,0xc7,0xca,0xcc,0xcf,0xd1,0xd4,0xd6,0xd8,0xda,0xdd,0xdf,0xe1,0xe3,0xe5,
0xe7,0xe9,0xea,0xec,0xee,0xef,0xf1,0xf2,0xf4,0xf5,0xf6,0xf7,0xf8,0xf9,0xfa,0xfb,0xfc,0xfd,0xfd,0xfe,0xff,
0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xfe,0xfd,0xfd,0xfc,0xfb,0xfa,0xf9,0xf8,0xf7,0xf6,
0xf5,0xf4,0xf2,0xf1,0xef,0xee,0xec,0xea,0xe9,0xe7,0xe5,0xe3,0xe1,0xde,0xdd,0xda,0xd8,0xd6,0xd4,0xd1,0xcf,
0xcc,0xca,0xc7,0xc5,0xc2,0xbf,0xbc,0xba,0xb7,0xb4,0xb1,0xae,0xab,0xa8,0xa5,0xa2,0x9f,0x9c,0x99,0x96,0x93,
0x90,0x8d,0x89,0x86,0x83,0x80,0x80,0x7c,0x79,0x76,0x72,0x6f,0x6c,0x69,0x66,0x63,0x60,0x5d,0x5a,0x57,0x55,
0x51,0x4e,0x4c,0x48,0x45,0x43,0x40,0x3d,0x3a,0x38,0x35,0x33,0x30,0x2e,0x2b,0x29,0x27,0x25,0x22,0x20,0x1e,
0x1c,0x1a,0x18,0x16,0x15,0x13,0x11,0x10,0x0e,0x0d,0x0b,0x0a,0x09,0x08,0x07,0x06,0x05,0x04,0x03,0x02,0x02,
0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x02,0x02,0x03,0x04,0x05,0x06,0x07,
0x08,0x09,0x0a,0x0b,0x0d,0x0e,0x10,0x11,0x13,0x15,0x16,0x18,0x1a,0x1c,0x1e,0x20,0x22,0x25,0x27,0x29,0x2b,
0x2e,0x30,0x33,0x35,0x38,0x3a,0x3d,0x40,0x43,0x45,0x48,0x4c,0x4e,0x51,0x55,0x57,0x5a,0x5d,0x60,0x63,0x66,
0x69,0x6c,0x6f,0x72,0x76,0x79,0x7c,0x80 };

void delay(uint x) //延時函數
{
while(x--);
}
void fangbo()    //方波
{
P0=0xff;
delay(1000);
P0=0x00;
delay(1000);
}
void sanjiao()    //三角波
{
uchar i;
while(1)
{
for(i=0;i<255;i++)
P0=i;
for(i=255;i>0;i--)
P0=i;
P0=0;
{
if(key1!=0)
break;
}
}
}
void juchi() //鋸齒波
{
uchar i;
while(1)
{
for(i=0;i<=255;i++)
{
     P0=i;
if(key2!=0)
break;
}

}
}
void zhengxian() //正弦波
{
uchar i;
while(1)
{
for(i=0;i<256;i++)
{
P0=Sin[i];
}

}
}
void dingshi0(void)  interrupt 1  using 1
{
   TH0=(65536-50000)/256;
   TL0=(65536-50000)%256; //50ms
   count++;
   if(count==20)
   {
         count=0;
   a++;
   }
}

void int0(void) interrupt 0  using 0
{
zhengxian();

}
void main()
{
TMOD=0X01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1; //開啟總中斷
ET0=1;       //開中斷ET0
TR0=1;    //啟動中斷ET0

EX0=1;    //外部中斷0
IT0=0;

P1=0xff;
while(1)
{
   if(a==1)
{
fangbo();
TR0=0;
}
if(key1==0)
{
sanjiao();
}
      if(key2==0)
{
juchi();
}

}

}