我的數碼管位和斷碼都為低電平時才亮（有點兒特殊）

紅外接收的頭接到INT0引腳

#include<reg52.h>

uchar irtime;
uchar startflag;
uchar irdata[33];
uchar bitnum;
uchar irreceok;
uchar ircode[4];
//uchar irprosok;
uchar disp[8];

uchar code duan[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
uchar code wei[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};

void delay_50ms(uint t)
{
 uint j;
 for(;t>0;t--)
  for(j=6245;j>0;j--);
}

void delay_50us(uint t)
{
 uchar j;
 for(;t>0;t--)
  for(j=19;j>0;j--);
 
}

void timer0init(void)
{
 TMOD=0x02;
 TH0=0;
 TL0=0;
 ET0=1;
 EA=1;
 TR0=1;
}

void int0init(void)
{
 IT0=1;
 EX0=1;
 EA=1;
}

void irpros(void)  //解碼
{
 uchar k,i,j,value;
 k=1;
 for(j=0;j<4;j++)
 {
  for(i=0;i<8;i++)
  {
   value=value>>1;    //相當于7次
   if(irdata[k]>6)
   {       //8次
    value=value  | 0x80;
   }
   k++;
  }
  ircode[j]=value;
 }
 //irprosok=1;
}

void irwork(void)
{
 disp[0]=ircode[0]/16;
 disp[1]=ircode[0]%16;
 disp[2]=ircode[1]/16;
 disp[3]=ircode[1]%16;
 disp[4]=ircode[2]/16;
 disp[5]=ircode[2]%16;
 disp[6]=ircode[3]/16;
 disp[7]=ircode[4]%16;
}

void display(void)
{
 uchar i;
 for(i=0;i<8;i++)
 {
   P1=duan[disp];
   P2=wei;
   delay_50us(20);
 }
}

void main()
{
 timer0init();
 int0init();
 while(1)
 {
    if(irreceok)
    {
      irpros();
   irreceok=0;
    }
    //if(irprosok)
    //{
      irwork();
  // irprosok=0;
    //}
  display();

 }
}

void timer0() interrupt 1
{
 irtime++;    // 最大255，等自加到255，又變0
}

void int0() interrupt 0
{
  startflag=0;
 if(startflag)
 {
  if(irtime>32) //檢測引導碼
  {
   bitnum=0; 
  }
  irdata[bitnum++]=irtime;
  irtime=0;

  if(bitnum==33)
  {
   bitnum=0;
   irreceok=1;
  }
 }
 else
 {
  startflag=1;
  irtime=0;
 }
}

我設計成功的紅外解碼程序，你對照一下吧。

#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int

unsigned char smg_du[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
unsigned char smg_we[]={0x00,0x10,0x20,0x30,0x40,0x50,0x60,0x70};

uchar irtime;
uchar startflag;
uchar irdata[33];
uchar bitnum;
uchar irreceok;
uchar ircode[4];
uchar irprosok;
uchar disp[8];