有人能看下這個程序怎么單個反白顯示？就是只反白那一行，移動到哪反白哪一行。

ID:272089 · 發表于 2018-11-22 19:18

就是那個not的幾行，老是一直掃描導致一直在閃，找不到好的方法。#include <REGX51.H>
#include <intrins.h>
#include <zimo.c>

#define uchar unsigned char
#define uint unsigned int

void delay(uint i){while(i--);}

sbit cs2=P2^3; sbit cs1=P2^4; sbit en=P2^5; sbit rw=P2^6; sbit rs=P2^7;
sbit row0=P3^0; sbit row1=P3^1; sbit col0=P3^2; sbit col1=P3^3; sbit col2=P3^4;
sbit col3=P3^5; sbit sw=P3^6;
sbit w1=P3^7; sbit w2=P2^0; sbit w3=P2^1; sbit w4=P2^2;
sbit wl1=P1^0; sbit wl2=P1^1; sbit wl3=P1^2; sbit wl4=P1^3;
sbit wl5=P1^4; sbit wl6=P1^5; sbit wl7=P1^6; sbit wl8=P1^7;

#define zuo {w1=0;w2=1;}
#define you {w1=1;w2=0;}
#define stop {w1=w2=1;}
#define jia {w3=0;}
#define song {w3=1;}
#define shang {w4=1;}
#define xia {w4=0;}

uchar key(void)
{
uchar k=0xff;
row0=0; k=col0==0?0:col1==0?1:col2==0?2:col3==0?3:k; row0=1;
row1=0; k=col0==0?4:col1==0?5:col2==0?6:col3==0?7:k; row1=1;
 return k;
}

void wc(uchar com)
{
 rs=0;rw=0;
 P0=com;
 en=1;en=0;
}

void wd(uchar dat)
{
 rs=1;rw=0;
 P0=dat;
 en=1;en=0;
}

void clr()
{
uchar i,j;
 cs1=cs2=1;
 for(i=0;i<8;i++)
 {
 wc(0xb8+i);
 wc(0x40);
 for(j=0;j<64;j++)wd(0);
 }
}
/** 將一字節數據dat寫到r行，c列 **/
void wo(uchar r,uchar c,uchar dat){
 if(c<64)cs1=1,cs2=0; //選擇左屏
 else cs1=0,cs2=1,c-=64; //選擇右屏
 wc(0xb8+r);
 wc(0x40+c);
 wd(dat);
}
/** 讀當顯示數據 **/
uchar read(uchar r,uchar c){
 uchar temp;
 if(c<64)cs1=1,cs2=0; //選擇左屏
 else cs1=0,cs2=1,c-=64; //選擇右屏
 wc(0xb8+r);
 wc(0x40+c);
 P0=0xFF;
 rs=1;rw=1;
 en=1;en=0;delay(1); //讀空操作
 en=1;temp=P0;en=0;//正式讀數據
 return temp;
}

/** 反白顯示，參數：r為頁號，n為跨頁數，c為起始列，w為寬度 **/
void not(uchar r,uchar n,uchar c,uchar w){
 uchar i,j=8;
 for(j=r;j<r+n;j++)
 for(i=c;i<c+w;i++)
 wo(j,i,~read(j,i));
}

void clr1(uchar row,uchar col,uchar x,uchar y)
{
uchar i,j;
cs1=cs2=1;
 for(i=0;i<y;i++)
 {
 wc(0xb8+row+i);
 wc(0x40+col);
 for(j=0;j<x;j++)wd(0);
 }
}

void init12864()
{
P0=0xff;
wc(0x3f);
 wc(0xc0);
 clr();
}

void showxy(uchar row,uchar col,uchar x,uchar y,uchar *tab)
{
uchar i,j;
 bit right;
 if(col<64)right=0;
 else {col-=64;right=1;}
 for(i=0;i<y;i++)
 {
 if(right)cs1=0,cs2=1;
 else cs1=1,cs2=0;
 wc(0xb8+row+i);
 wc(0x40+col);
 for(j=0;j<x;j++)
 {
 if(col+j<64)wd(tab[i*x+j]);
 else if(right==0)
 {
 cs1=0;cs2=1;
 wc(0xb8+row+i);
 wc(0x40+(col+j-64));
 wd(tab[i*x+j]);
 }
 }
 }
}

void menu0()
{
showxy(0,0,16,2,zm16x16[15]);
 showxy(0,16,16,2,zm16x16[16]);
 showxy(0,32,16,2,zm16x16[17]);
 showxy(0,48,16,2,zm16x16[18]);
 showxy(0,64,16,2,zm16x16[19]);
}
void menu1()
{
 showxy(0,40,16,2,zm16x16[20]);
 showxy(0,56,16,2,zm16x16[21]);
 showxy(0,72,16,2,zm16x16[22]);

 showxy(2,0,16,2,zm16x16[23]);
 showxy(2,16,16,2,zm16x16[24]);

 showxy(4,0,16,2,zm16x16[25]);
 showxy(4,16,16,2,zm16x16[26]);
}

void menu2()
{
 showxy(0,32,16,2,zm16x16[23]);
 showxy(0,48,16,2,zm16x16[24]);
 showxy(0,64,16,2,zm16x16[21]);
 showxy(0,80,16,2,zm16x16[22]);

 showxy(2,0,16,2,zm16x16[27]);
 showxy(2,16,16,2,zm16x16[28]);
 showxy(2,32,16,2,zm16x16[29]);
 showxy(2,48,16,2,zm16x16[30]);
 showxy(2,64,16,2,zm16x16[23]);
 showxy(2,80,16,2,zm16x16[24]);

 showxy(4,0,16,2,zm16x16[31]);
 showxy(4,16,16,2,zm16x16[28]);
 showxy(4,32,16,2,zm16x16[27]);
 showxy(4,48,16,2,zm16x16[32]);
 showxy(4,64,16,2,zm16x16[30]);
 showxy(4,80,16,2,zm16x16[23]);
 showxy(4,96,16,2,zm16x16[24]);

showxy(6,0,16,2,zm16x16[19]);
 showxy(6,16,16,2,zm16x16[33]);
 showxy(6,32,16,2,zm16x16[34]);
 showxy(6,48,16,2,zm16x16[35]);
 showxy(6,64,16,2,zm16x16[23]);
 showxy(6,80,16,2,zm16x16[24]);
}

uchar j=0,ci=0,row=2,col=0,q=0,y;

void main()
{
init12864();
 delay(1);
 while(1)
 {
 while(sw==1)
 {
 while(ci==0){clr();menu0();ci++;}
 q=0;
 j=0;
 }
 while(sw==0)
 {
 switch(q)
 {
 case 0:
 while(j==0){clr();j++;}
 menu1();
 if(key()==4||key()==0)q=1;
 break;
 case 1:
 if(row<4&&key()==4){row+=2;}
 else if(row>2&&key()==0){row-=2;}
 else if(key()==2&row==2)q=2;
 else if(key()==2&row==4)q=20;
 if(row==4)not(4,2,0,127);
 else if(row==2)not(2,2,0,127);
 break;
 case 2:
 clr();
 menu2();
 q=4;
 case 4:
 if(row<6&&key()==4){while(key()==4);row+=2;}
 else if(row>2&&key()==0){while(key()==0);row-=2;}

 if(row==4)not(4,2,0,127);
 else if(row==2)not(2,2,0,127);
 else if(row==6)not(6,2,0,127);

 }
 ci=0;
 }
 }
}
// 1516171819202122232425262728293031323334353637383940414243
//uchar code zm16x16l[]="系統待機中主菜單設置運行裝箱總數每瓶獎幾率有狀態共第點";

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有人能看下這個程序怎么單個反白顯示？就是只反白那一行，移動到哪反白哪一行。