11種花樣流水燈的C程序和單片機仿真

ID:121859 · 發表于 2018-1-18 10:37

常見的流水燈形式組合在一起，12個LED，滿足你多種需求，提供一個大家對于大于8個LED燈進行流水燈控制的思路。
仿真原理圖如下（proteus仿真工程文件可到本帖附件中下載）

單片機源程序如下:

#include<reg51.h>
#define uchar unsigned char
uchar code ledtab[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0x88,0x83,0xc6,0xa1,0x86,0x8e,0xff};
uchar fun=0,time=0,num=0,ss;
uchar code led1[6]={0xfe,0xfd,0xfb,0xf7,0x6f,0x9f};
uchar led2=0xfe;
sbit key=P3^2;
void delay(uchar a)
{
uchar i;
while(a--)for(i=0;i<120;i++);
}
void t0isr() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
time++;
if(time>=2)
{
time=0;
switch(fun)
{
case 0: num%=6;
P1=led1[num];
if(num<4)P0=led1[num];
else P0=0xff;
break;
case 1: P1=ss;P0=ss;ss=~ss;break;
case 2: num%=12;
if(num<4)
{
if(num==0)led2=0xfe;
P0=led2;
P1=0xff;
led2<<=1;
led2|=0x01;
}
else
{
if(num==4)led2=0x7f;
P0=0xff;
P1=led2;
led2>>=1;
led2|=0x80;
}
break;
case 3: num%=12;
if(num<8)
{
if(num==0)led2=0xfe;
P0=0xff;
P1=led2;
led2<<=1;
led2|=0x01;
}
else
{
if(num==8)led2=0xf7;
P1=0xff;
P0=led2;
led2>>=1;
led2|=0x08;
}
break;
case 4: num%=2;
if(num==0){P1=0xc0;P0=0xff;}
else{P1=0x3f;P0=0x00;}
break;
case 5: num%=7;
if(num==0){P0=0x00;P1=0x00;led2=0x01;}
else
{
if(num<5){P0=led2;P1=led2;led2<<=1;led2|=0x01;}
else
{
if(num==5){P1=0x9f;P0=0xff;}
if(num==6)P1=0xff;
}
}
break;
case 6: num%=13;
if(num<9){
if(num==0){P0=0x00;P1=0x00;led2=0x01;}
else{P1=led2;
led2<<=1;
led2|=0x01;
}
}
else
{
if(num==9)led2=0xf8;
P0=led2;
led2>>=1;
led2|=0x08;
}
break;
case 7: num%=13;
if(num<5)
{
if(num==0){P0=0x00;P1=0x00;led2=0x01;}
else{P0=led2;led2<<=1;led2|=0x01;}
}
else
{
if(num==5)led2=0x80;
P1=led2;
led2>>=1;
led2|=0x80;
}
break;
case 8: num%=7;
if(num==0){P0=0xff;P1=0xff;led2=0x07;}
if(num==1)P1=0x9f;
if(num==2)P1=0x0f;
if(num>2){P0=led2;P1=led2;led2>>=1;led2&=0xf7;}
break;
case 9: num%=7;
if(num<5)
{
if(num==0){P0=0xff;P1=0xff;led2=0xfe;}
else
{
P1=led2;P0=led2;led2<<=1;
}
}
else
{
if(num==5){P0=0x00;P1=0x60;}
if(num==6)P1=0x00;
}
break;
case 10: num%=2;
if(num==0){P0=0xf5;P1=0xaa;}
else {P0=0xfa;P1=0x55;}
default:break;
}
num++;
}
}
main()
{
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
TR0=1;
……………………
…………限于本文篇幅余下代碼請從51黑下載附件…………