這是在矩陣鍵盤1位數(shù)碼管顯示鍵值0~F的程序上改的，6位數(shù)碼管顯示，只能保存6次鍵值，超出6次前面的溢出。
#include <AT89X52.H>
#define uint unsigned int //宏定義無符號整型數(shù)據(jù)
#define uchar unsigned char //宏定義無符號字符型數(shù)據(jù)
sbit dula=P2^6; //數(shù)碼管段鎖存
sbit wela=P2^7; //數(shù)碼管位鎖存
uchar code table[]={ //共陰數(shù)碼管(0~F.-)
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71,0x80,0x40};
uchar key=17,key1=17,key2=17,key3=17,key4=17,key5=17,key6=17;
void keyscan() //按鍵掃描程序
{
static bit sign=0; //按鍵有效標志
static uint count=0; //消抖計數(shù)變量
uchar num=0; //臨時變量
P3=0xf0; //賦值P3 1111 0000
if(P3!=0xf0) //檢測按鍵按下并有效
{
count++; //消抖計數(shù)
if((count>=500)&&(sign==0)) //100~1000，根據(jù)主循環(huán)周期調整約10~20ms
{ //按鍵有效標志0
sign=1; //按鍵有效標志置1
num=P3; //保存P3值xxxx 0000，x為0或1
num|=0x0f; //保存num按位或0x0f值xxxx 1111
P3=num; //賦值P3 xxxx 1111
num=P3; //保存P3值xxxx xxxx
switch(num)
{
case 0xee: key= 0; break;
case 0xde: key= 1; break;
case 0xbe: key= 2; break;
case 0x7e: key= 3; break;
case 0xed: key= 4; break;
case 0xdd: key= 5; break;
case 0xbd: key= 6; break;
case 0x7d: key= 7; break;
case 0xeb: key= 8; break;
case 0xdb: key= 9; break;
case 0xbb: key=10; break;
case 0x7b: key=11; break;
case 0xe7: key=12; break;
case 0xd7: key=13; break;
case 0xb7: key=14; break;
case 0x77: key=15; break;
}
key6=key5;key5=key4;key4=key3;//轉移保存鍵值
key3=key2;key2=key1;key1=key;
}
}
else //鍵抬起
{
sign=0; //按鍵有效標志清0
count=0; //消抖計數(shù)清0
}
}
void Timer0Init() //2毫秒@11.0592MHz
{
TMOD= 0x01; //設置定時器模式
TL0 = 0xCD; //設置定時初值
TH0 = 0xF8; //設置定時初值
TF0 = 0; //清除TF0標志
TR0 = 1; //定時器0開始計時
EA=1; //開總中斷
ET0=1; //開定時器0中斷
}
void display()
{
static uchar count=0; //計數(shù)變量
switch(count)
{
case 0:
P0=table[key6];
dula=1;
dula=0;
P0=0x7e;
wela=1;
wela=0;
count++;
break;
case 1:
P0=table[key5];
dula=1;
dula=0;
P0=0x7d;
wela=1;
wela=0;
count++;
break;
case 2:
P0=table[key4];
dula=1;
dula=0;
P0=0x7b;
wela=1;
wela=0;
count++;
break;
case 3:
P0=table[key3];
dula=1;
dula=0;
P0=0x77;
wela=1;
wela=0;
count++;
break;
case 4:
P0=table[key2];
dula=1;
dula=0;
P0=0xef;
wela=1;
wela=0;
count++;
break;
case 5:
P0=table[key1];
dula=1;
dula=0;
P0=0xdf;
wela=1;
wela=0;
count=0;
break;
}
}
void main() //主函數(shù)
{
Timer0Init();
while(1)
{
keyscan(); //按鍵掃描程序
// display(); //1位數(shù)碼管顯示程序
}
}
void timer0() interrupt 1
{
TL0 = 0xCD; //設置定時初值
TH0 = 0xF8; //設置定時初值
display(); //6位數(shù)碼管顯示程序
} |
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